When Line 1 trips while carrying 1000 MW from Station A to Load, how much of the power will flow on Line 2 with its impedance?

When Line 1 trips while carrying 1000 MW from Station A to Load, the power flow on Line 2 depends on its electrical characteristics, particularly its impedance. In power systems, when one line becomes unavailable (in this case, Line 1), the remaining lines must compensate for the lost load by sharing the power flow based on their impedance.

If Line 2 has a certain level of impedance that allows it to carry a portion of the load, it will share the total power based on the relative impedances of the lines connected to the same system. Commonly, when there are two parallel lines, the load will divide in inverse proportion to their impedances.

Assuming that Line 2's impedance allows it to take on a calculated portion of the 1000 MW that was previously flowing through Line 1, 550 MW flowing on Line 2 indicates that it can handle more power in relation to its impedance than just half of the total load. The fact that this scenario results in Line 2 carrying a total of 550 MW reflects the system's ability to reallocate power efficiently based on the impedance characteristics.

Thus, when Line 1 trips, Line 2 takes up the slack by transferring 550 MW to maintain grid